Plug in into the first equation In other words, replace each with Notice we've eliminated the variables So we now have a simple equation with one unknown Notice if we graph the two equations, we can see that their intersection is at So this verifies our answerAbout the xaxisFind the volume of the solid obtained by rotating theregion bounded by the given curves about the specified line SketSOLUTION y=x1 2xy=0 You can put this solution on YOUR website!
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Y^2=6x y=0 x=1 x=3- 3/x 1/y 9 = 0, 2/x 3/y = 5 linear equations in two variables;You can put this solution on YOUR website!
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Conditioning on the discrete level Example A fair coin is tossed 10 times; See the answer below How do you use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by #y = x^3Precalculus Solve by Graphing y=x3 , y=x1 y = x − 3 y = x 3 , y = −x − 1 y = x 1 Create a graph to locate the intersection of the equations The intersection of the system of equations is the solution (1,−2) ( 1, 2)
The solution is x = 1 and y = 3 There is no solution There are Algebra/Precalculus Solve the system of linear equations and check any solutions algebraically (If there is no solution, enter NO SOLUTION If the system is dependent, express x, y, and z in terms of the parameter a) 3x3y6z=6 x2yz=8 5x8y13z=4Vertical asymptote at x = 3 horizontal asymptote at y = 1 Explanation For y \displaystyle=\frac{{x}}{{{x}{3}}} The denominator of y cannot be zero as this is undefined Equating the vertical asymptote at x = 3 horizontal asymptote at y = 1 Explanation For y = x − 3 x The denominator of y cannot be zero as this is undefinedSolution Steps y = ( x ^ { 2 } 1 ) ( x ^ { 3 } 1 ) y = ( x 2 1) ( x 3 − 1) Use the distributive property to multiply x^ {2}1 by x^ {3}1 Use the distributive property to multiply x 2 1 by x 3 − 1 y=x^ {5}x^ {2}x^ {3}1 y = x 5 − x 2 x 3 − 1
Solve by Substitution 2xy=3 , xy=0 2x − y = −3 2 x y = 3 , x y = 0 x y = 0 Subtract y y from both sides of the equation x = −y x = y 2x−y = −3 2 x y = 3 Replace all occurrences of x x with −y y in each equation Tap for more steps Replace all occurrences of x x in 2 x − y = − 3 2 x y = 3 with − yStep by step solution of a set of 2, 3 or 4 Linear Equations using the Substitution Method 2xy=1;3xy=2 Tiger Algebra SolverY=x^3 Y=0 X=1 About X=2;
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See the answer y=x^3 y=0 x=1 x=2 about y axis Expert Answer 100% (2 ratings) Previous question Next question Get more help from Chegg Solve it with our calculus problem solver and calculatorTrying to factor by splitting the middle term 21 Factoring 2x23x1 The first term is, 2x2 its coefficient is 2 The middle term is, 3x its coefficient is 3 The last term, "the constant", is 1 Step1 Multiply the coefficient of the first term by the constant 2 • 1 = 2 Step2 Find two factors of 2 whose sum equals the coefficient When I set y ( x) = A x u ( x) = A u x , (I think this is how you solve second order with variable coefficients) I got to the point u ″ ( x − x 3) 2 u ′ ( 1 − 2 x 2) = u ″ ( x − x 3) 2 u ′ ( 1 − 3 x 2) 2 u ′ x 2 = d d x u ′ ( x − x 3) 2 u ′ ( 1 − x 2) = 0 Then I let u ′ = w and got w ′ ( x − x 3
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Free system of equations calculator solve system of equations stepbystepY=3/2x2;y=1/2x2 Simple and best practice solution for y=3/2x2;y=1/2x2 Check how easy it is, to solve this system of equations and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework y = ± √ ( 1 x^2) *C 2 1 y (x) = ± √ C 2 x^2 C 2 1 Nowsince the intial condition is that y (0) = √3 the positive root must be correctsolving for C 2, we have that
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Steps for Solving Linear Equation y=2x1 y = 2 x − 1 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2x1=y 2 x − 1 = y Add 1 to both sides Add 1 to both sidesGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us! Ex 21, 1 If (x/3 " 1, y –" 2/3) = (5/3 "," 1/3) , find the values of x and y (x/3 " 1, y –" 2/3) = (5/3 "," 1/3) Since the ordered pairs are equal, corresponding elements are equal Hence x/3 1 = 5/3 x/3 = 5/3 – 1 x/3 = 2/3 x = 2 y – 2/3 = 1/3 y = 1/3 2/3 y = 3/3 y = 1 Show More
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